Let f(x)=x+7 and g(x)=x-4 Find f(x) x g(x) A. X^2-3x-28
B. x^2-3x-11
C. x^2+3x-28
D. x^2+3x-11

C. x²+3x-28

Step-by-step explanation:

f(x) = x +7

g(x) = x -4

f(x) · g(x) = (x-4)(x+7)

              = x²+7x-4x-28

              = x²+3x-28

idk

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204