Which equation shows direct variation? Choose 1
Choose 1

(Choice A)
A
\dfrac{x}{y} = 3
y
x

=3start fraction, x, divided by, y, end fraction, equals, 3

(Choice B)
B
x \cdot y = \dfrac{1}{3}x⋅y=
3
1

x, dot, y, equals, start fraction, 1, divided by, 3, end fraction

(Choice C)
C
\dfrac{1}{3} \cdot \dfrac{1}{x} = y
3
1

⋅
x
1

=ystart fraction, 1, divided by, 3, end fraction, dot, start fraction, 1, divided by, x, end fraction, equals, y

(Choice D)
D
x + y = \dfrac{1}{3}x+y=
3
1

x, plus, y, equals, start fraction, 1, divided by, 3, end fraction

(Choice E)
E
3 \cdot \dfrac{1}{x} = y3⋅
x
1

=y