27)
at 6: 00 a. m. the temperature was 33°f. by noon the temperature had increased by 10°f and by 3: 00 p. m. it had increased another 12°f. if at 10: 00 p. m. the temperature had decreased by 15°f, how much does the temperature need to rise or fall to return to the original temperature of 33°f?

it would fall by 7°F

Step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.