In a right triangle the length of a hypotenuse is c and the length of one leg is a, and the length of the other leg is b, what is the value of b, if a=2sqrt3 , c=2b ?

b = √6

Step-by-step explanation: Use the Pythagorean Theorem to solve this.

a² + b² = c²

Plug in your values:

2√3² + b² = 2b²

When a square root is squared, the square root is cancelled out so you will be left with this:

2(3) + b² = 2b²

Subtract b² from both sides so you’re left with:

6 = b²

Now, to get rid of the square, just square root both sides:

√6 = √b²

Since the √6 is not a perfect square, leave it in the radical. Then, you get your

b = √6

the b is equivalent to 2

.5 lb

step-by-step explanation:

12 in / 6 in =2 in

.25 x 2 = .5 lb

32

step-by-step explanation: