9 A wagon is accelerating down a hill at constant acceleration. It took is more to accelerate from a velocity of I m/s to a velocity of 5 m/s than it took to accelerate from rest to a velocity of 1m/s. find the acceleration

3 m/s²

Step-by-step explanation:

"It took 1 s more to accelerate from a velocity of 1 m/s to a velocity of 5 m/s than it took to accelerate from rest to a velocity of 1 m/s.  Find the acceleration."

Acceleration is equal to change in velocity over change in time.  The acceleration is constant, so we can write a proportion:

(1 m/s − 0 m/s) / t = (5 m/s − 1 m/s) / (t + 1 s)

1 / t = 4 / (t + 1)

4t = t + 1

3t = 1

t = ⅓

The acceleration is therefore:

a = Δv / Δt

a = (1 m/s − 0 m/s) / (⅓ s)

a = 3 m/s²

do you have a picture of the table