Using this and the knowledge that 32° F = 0°C and 212°F = 100°C, find an equation that computes Celsius temperature in terms of Fahrenheit temperature; i. e., an equation of the form C = “an expression involving only the variable F.” c=(f-32)/1.8

Likewise, find an equation that computes Fahrenheit temperature in terms of Celsius temperature; i. e. an equation of the form F = “an expression involving only the variable C.”
f=1.8c+32

(a) How cold was it in Oslo in °F?

(b) What temperature is it the same in °F and °C?

(a)

Step-by-step explanation:

answer:

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)