Kim's softball team was playing in the championship game. When there were 4 innings left, the team was losing by a score of 17 to 6 points. In the last 4 innings, her team scored the same number of points per inning, and the other team did not score any more points. Kim's team won with the most points. Write an inequality to determine the number of points per inning, ppp, Kim's team could have scored. Write an inequality to determine the number of points per inning, ppp, Kim's team could have scor Find the minimum whole number of points per inning Kim's team could have scored.

3

Step-by-step explanation:

Given the following :

Score when there were 4 innings left = 17 to 6

Kim's team = 6 ; opposition team = 17

Opposition didn't score any point in the last 4 innings

Kim's team scored same number of points per inning and also won with the most points

Minimum Number of points Kim's team could have scored per inning :

Let number of points scored in each of the last 4 innings = p

Since they also won eventually:

Then

4p + initial points > opposition point

4p + 6 > 17

4p > 17 - 6

4p > 11

p > 11/4

p > 2.75

Hence, the minimum number of points Kim's team could have scored per inning in the last 4 would be 3( nearest whole number)

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.