The length of a rectangle is 5 more than twice the width. If the perimeter of the rectangle is 34, what is the length?

The dimensions of the rectangle are two unknowns: The length "l" and the width "w"

The perimeter of a rectangle is found as P = 2*l + 2*w

We also know that the length is 5cm more than twice the width. l = 2*w + 5

These two equations gives us a system of linear equations.

P = 2*l + 2*w

l = 2*w + 5

We can use substitution to replace the "l" in the first equation with 2*w + 5

P = 2*(2*w + 5) + 2*w

P = 4*w + 10 + 2*w

P = 6*w + 10

We know that P = 34cm

34 = 6*w + 10

Subtract 10 from both sides

24 = 6 * w

Divide both sides by 6

4 = w

Now that we know the width, we can find the length by substituting 4 for "w" in the second equation.

l = 2*4 + 5

l = 8 + 5

l = 13

The dimensions of the rectangle is 13cm x 4cm

the answer is 16ft

step-by-step explanation:

using pemdas, (order of operations) you'll see the answer is 24.