A given line has the equation 10x+2y=-2. What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0,
12)?
VX
O y=-5x+12
O 5x+y=12
O y-12=5(x-0)
O 5x+y=-1

Step-by-step explanation:

y=-5x+12

10x+2y=-2

Subtract 10x to the other side of the equation and you will get 2y=-10x-2

Then divide both side by 2 to get y by itself

It will lead you to y=-5x+1

Notice that your point is (0,12) and it says parallel so you will keep your slope but your y-intercept will change

Final y=-5x+12

I believe it's y= -5x+12. I really hope this helps. Happy schooling!!

the perimeter is increased by a factor of 2