In ΔJKL, \text{m}\angle J = (8x+6)^{\circ}m∠J=(8x+6)
∘
, \text{m}\angle K = (2x+2)^{\circ}m∠K...
Mathematics, 16.10.2020 01:01 kvngsavage156
In ΔJKL, \text{m}\angle J = (8x+6)^{\circ}m∠J=(8x+6)
∘
, \text{m}\angle K = (2x+2)^{\circ}m∠K=(2x+2)
∘
, and \text{m}\angle L = (4x+4)^{\circ}m∠L=(4x+4)
∘
. Find \text{m}\angle L. m∠L.
Answers: 1
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