−14a−(−48a)
mind helping

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

Step-by-step explanation:

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.