The roots of x² - 4x = 5, in ascending order, are what?? PLEASE HELP

We want to find the roots of a quadratic equation, to do that, we will use the Bhaskara's formula.

For an equation like a*x^2 + b*x + c = 0

The solutions are given by:

Using that formula we will get that the solutions in ascending order are -1 and 5.

Now let's see how to get that:

We have expression: x^2 - 4x = 5

We can rewrite this as:

x^2 - 4x - 5 = 0

Now we can use the Bhaskara's formula to get:

Then the two solutions are:

x = (4 + 6)/2 = 5

x = (4 - 6)/2 = -1

Then the solutions in ascending order are -1 and 5.

If you want to learn more, you can read:

link

Step-by-step explanation:

x^2 - 4x - 5 = 0

(x - 5)(x + 1) = 0

x - 5 = 0

x = 5

x + 1 = 0

x = -1

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47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)