There is a group of kids who 64% of them have blue cars /!and another group with 1.8% red cars group A doesn’t have red car and group B doesn’t have blue cars. The rest have different color. 1- what is the probability of selecting a kid who has red car?
2- let’s say you pick a kid randomly what’s the probability of one them having a red car and the other blue?
3- what the probability of selecting one that has blue or red car at home?
4- let’s say you randomly selected 8 students what’s the probability of one of them having a blue car at home?

has red car?

2- let’s say you pick a kid randomly what’s the probability of one them having a red car and the other blue?

3- what the probability of selecting one that has blue or red car at home?

4- let’s say you randomly selected 8 students what’s the probability of one of them having a blue car at home?

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation: