Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b? –21
–4
11
27

Find the slope that passes between the points.

(y₂ - y₁) / (x₂ - x₁)

J(-4, -5)

K(-6, 3)

(3 - (-5)) / (-6 - (-4))

(3 + 5) / (-6 + 4)

8 / -2

-4

Now slap that slope into the formula and substitute on of the coordinates to the formula to solve for b (I'll take point K's coordinate):

y = mx + b

y = -4x + b

3 = -4(-6) + b

3 = 24 + b

3 - 24 = b

- 21 = b

b = -21

me

step-by-step explanation:

step-by-step explanation: