In ΔBCD, \overline{BD} BD is extended through point D to point E, \text{m}\angle CDE = (9x-12)^{\circ}m∠CDE=(9x−12) ∘ , \text{m}\angle BCD = (2x+3)^{\circ}m∠BCD=(2x+3) ∘ , and \text{m}\angle DBC = (3x+5)^{\circ}m∠DBC=(3x+5) ∘ . Find \text{m}\angle BCD. M∠BCD.

Angle BCD is 13 degrees

Step-by-step explanation:

Here, we want to find the measure of angle BCD

To get this, we need an appropriate diagram. The diagram can be seen in the attachment.

To find the value of BCD, we can use an important triangle theorem.

This is that the sum of opposite interior angles of a triangle equals the exterior angle.

Thus, we have that;

BCD + DBC = CDE

hence;

3x + 5 + 2x + 3 = 9x-12

5x + 8 = 9x -12

9x-5x = 8 + 12

4x = 20

x = 20/4

x = 5

So the measure of BCD will be 2(5) + 3 = 10 + 3 = 13

555.99.

step-by-step explanation:

hope this

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get