9) There are six girls and 12 boys in Ms. Jeffry's environmental club. She wants to divide the students into groups with the same number of boys and the same number of girls in each group. What is the maximum number of groups she can make? *

No . of girls in Ms. Jeffry's environmental club = 6

No . of boys in Ms. Jeffry's environmental club = 12

To find the maximum number of groups she can make , we have to find the highest common factor ( HCF ) of the number of boys and girls in her club .

Factors of 6 = 1 , 2 , 3 and 6

Factors of 12 = 2 , 3 , 4 , 6 and 12

Hence the highest common factor of 6 and 12 are 6 .

Therefore , the maximum number of groups Ms . Jeffry can make where the number of girls and boys are same are 6 .

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."