Pentagon pqrst and its reflection, pentagon p'q'r's't', are shown in the coordinate plane below:
what is the line of reflection between pentagons pqrst and p'q'r's't'?
a)y = x
b)y = 0
c)x = 1
d)x = 0

Option A y = x

Step-by-step explanation:

In the given figure Pentagon PQRST and its reflection Pentagon P'Q'R'S'T' have been shown.

Pentagon P'Q'R'S'T' have been reflected by a line that passes through origin (0,0) and is perpendicular to the line joining points  S(-2,1) and S'(1,-2)

Let the line is y = mx + c

Since line passing through s and s' and slope = = = -1

So line perpendicular to SS' will be

m × (-1) = (-1)

m = 1

The given line will be y = x + c

Since this line passes through (0,0) origin so 'C' will be zero.

Now we can say equation of the line is y = x by which Pentagon PQRST has been reflected.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50