Write the point-slope form of the line that passes through (-8, 2) and is perpendicular to a line with a slope of -8. Include all of your work in your final answer. Type your answer in the box provided to submit your solution.

y-2= 1/8(x+8)

Step-by-step explanation:

First, you must find the slope of the line. If it is perpendicular to a line with a slope of -8, the slope must be 1/8. A perpendicular slope means the opposite inverse slope, meaning you switch the numerator and denominator and you switch it from negative to positive.

Second, you plug in the points into the point-slope formula. The formula is

y-y1=m (x-x1). You end up with the answer y-2 =1/8(x+8)

I hope this helps let me know if you have any questions!

y - 2 = 1/8(x+8)

Step-by-step explanation:

The slope of lines that are perpendicular are each other's opposite reciprocal.

so, the reciprocal of -8 = -1/8, then find the opposite of -1/8 which is 1/8.

Point-slope form : y - y1 = m(x - x1)

(x1,y1) = (-8,2)

so, y - 2 = 1/8(x+8) is our final answer!

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.