What is the value of h(−2) when h(x)=3x+1? Enter your answer in the box.

h(−2)=

The value of h(−2) when h(x)=3x+1 is h(-2) = -5

From the question,

The given function is h(x)=3x+1

To determine the value of h(-2), we will put x = -2 and evaluate

From

h(x)=3x+1

h(-2) becomes

h(-2)=3(-2) + 1

h(-2) = (3× -2) + 1

h(-2) = (-6) + 1

h(-2) = -6 + 1

h(-2) = -5

Hence, the value of h(−2) when h(x)=3x+1 is h(-2) = -5

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-5

Step-by-step explanation:

The answer is -5 because we have -2 as x. The function is h(x)=3x+1. 3 times -2=-6. When we add 1 to the result, we have -5 as the answer. Hope it helps!

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step-by-step explanation:

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