Consider this polynomial equation
6(x-3)(x^2+4)(x+1)=0
the equation has ( A. 2 B.3 C.4)...
Mathematics, 16.10.2020 18:01 freeman36
Consider this polynomial equation
6(x-3)(x^2+4)(x+1)=0
the equation has ( A. 2 B.3 C.4) solutions. it's real solutions are x = (-2 -1 and 2 or. -1 and 3)
Answers: 3
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