Rasha and Scott went to a bakery. Rasha bought 4 plain bagels and 2 chocolate donuts for a total of $8.70. Scott bought 3 chocolate donuts for a total of $2.55.
What is the cost of one plain bagel at the bakery?

Step-by-step explanation:

Let b = bagels , d = donuts

Rasha bought 4 plain bagels and 2 chocolate donuts for a total of $8.70

We can write this as :

4b + 2d = 8.70

Scott bought 3 chocolate donuts for $2.55

3d = 2.55

First, let's find out the cost of 1 donut.

To do this, divide 2.55 by 3.

1d = 2.55/3 =0.85  (1 donut costs $0.85)

Substitute the value of d ( d = 0.85 ) into the equation 4b + 2d = 8.70

4b + 2d = 8.70

4b + 2 (0.85) = 8.70

4b + 1.7 = 8.70

Subtract 1.7 from both sides.

4b = 8.70 - 1.7

4b = 7

Divide both sides by 4 to find how much one bagel costs.

b = 7/4 = 1.75

Therefore, one bagel costs $1.75

2.56 is the width of the garden

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: