As x approaches infinity, for which function does f(x) approach negative infinity? Select all that apply. Select all that apply: f(x)=19x(3x+7)(x+12) f(x)=−23(x+4)(x−1)(x−5) f(x)=3x(x+4)(x+7)(x−9) f(x)=(4x−7)(3x+1)(2x−11) f(x)=−29x(2x+5)(2x−1)(x+8)(x−1)(x+4 ) f(x)=−45x(x+1)(x+5)(x+8)(2x+5)(2x−7 )(4x+1)

Answer and explanation:

Please find answer and explanation attached

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

a

step-by-step explanation:

the answer is a