A school group wants to rent part of a bowling alley to have a party. The bowling alley costs $500 to rent, plus an additional charge of $5 per student to bowl. The group doesn’t want any student to pay more than $15 total to attend this party. What is inequality that could represent this situation?
How many students would need to attend so each student would pay at most $15?

If there are N students, the total cost will be:

C(N) = $500 + $5*N.

And we want the amount that each student pays to be equal or less than $15.

then:

C(N)/N ≤ $15.

Then the inequality that represents this situation is:

($500 + $5*N)/N ≤ $15.

Now, let's solve this:

($500 + $5*N) ≤ $15*N

$500 ≤ $15*N - $5*N

$500 ≤ $10*N

$500/$10 ≤ N

50 ≤ N

So the minimum number of students needed is 50.

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer