You and your neighbor attempt to use your cordless phones at the same time. Your phones independently select one of ten channels at random to connect to the base unit. What is the probability that both phones pick the same channel

1/100.

Step-by-step explanation:

So, we can make the following deductions from the information given in the question or problem above.

[1]. "You and your neighbor attempt to use your cordless phones at the same time."

DEDUCTION: Two people are involved, that is you and your neighbor are both involved.

[2]. "Your phones independently select one of ten channels at random to connect to the base unit. "

DEDUCTION: Both cordless phones can choose one channels each which is random. The number of channels available is ten.

Therefore, the probability that both your phone and your neighbor phone pick the same channel can be calculated or determined as follows:

The probability that both your phone and your neighbor phone pick the same channel = probability that both your phone will pick one channel out of the ten channels ×  the probability that your neighbor phone pick one channel out of the ten channels.

The probability that both your phone and your neighbor phone pick the same channel = 1/10 × 1/10 = 1/100.

Therefore, The probability that both your phone and your neighbor phone pick the same channel = 1/100.

3.4 pizzas

step-by-step explanation:

given is a scatter plot showing number of pizzas sold during weeks for different issues of coupon

y represents number of pizzas sold and x number of coupons issued

y is marked verticaly and x horizontally

the trend line is given as

y =3.4x+43

this says that even when no coupon is issued pizzas sold will be 43

and rate of change of pizza sold for 1 unit of coupon = slope = 3.4

i.e. when x increases by 1 unit y increases by 3.4 units

hence for each additional coupon issued 3.4 pizzas more will be sold

30005

yes ok