The lengths of salamanders have a normal distribution with mean 15cm, and standard deviation 2cm. What is the probability a salamander has length between 12.2cm and 16.5cm

The probability a salamander has a length between 12.2cm and 16.5cm is 0.6930

Step-by-step explanation:

We start by finding the z-score of each

Mathematically;

z-score = (x - mean)/SD

for 12.2 cm

z-score = (12.2 - 15)/2 = -2.8/2 = -1.4

For 16.5 cm

z-score = (16.5 -15)/2 = 1.5/2 = 0.75

So the probability we want to calculate is;

P( -1.4 < z < 0.75)

we can calculate this using the normal distribution table

Mathematically;

P( -1.4 < z < 0.75) = P( z < 0.75) - P( z < -1.4)

= 0.2263 + 0.30738

= 0.69262

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.