Which of the following equations have no solution? Check all that apply. A.6x + 1 = 3(2x – 4)
B.2 – 5x = 7x – 12
C.4(3 – x) = 2(6 – 2x)
D.5(x + 2) = 2(x – 4)
E.–4(x + 3) = 4(–x – 1)

6x + 1 = 3(2x – 4), 4(3 – x) = 2(6 – 2x), and −4(x+3)=4(−x−1)

Step-by-step explanation:

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation: