4(x + 3) − 7 ≥ x + 3(x + 1)

Here, we are required to determine the value of x from the inequality 4(x + 3) − 7 ≥ x + 3(x + 1)

By expansion of both sides of the equation;

4(x+3) - 7 ≥ x + 3(x+1)

4x + 12 - 7 ≥ x + 3x + 3

4x + 5 ≥ 4x + 3

From the polynomial; Since 4x cancels out 4x on both sides;

The inequality is correct because 5 ≥ 3.

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All real numbers are solutions.

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