1) Five less than twice a number is equal to one more than the number. What is the number? 2) Find the number of Calories in a stalk of celery and in a carrot given the following information.
A carrot has 13 Calories more than a celery stalk.
Five carrots and ten celery stalks have only 170 Calories.

3) Roger spent $22 on a baseball mitt and a softball. If the mitt cost $2 less than 5 times the cost of the softball, find the cost of each.

4) Find the total weight of the boxes of pecans in a shipment of 3 lb boxes of pecans and 2 lb boxes of walnuts.
There were 24 fewer 2 lb boxes of walnuts than 3 lb boxes of pecans.
The total weight of the shipment was 462 lb.

You can use the following chart to help you get started.

Weight per box Numer of boxes Total Weight
Pecans
Walnuts

if he has no friends he cant give them out to his friends

step-by-step explanation:

no friends = cant give anything out

i think 5 miles per hour

step-by-step explanation:

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.

the answer is b