Ivan has 32 baseballs and 48 basketballs. If he wants to divide them into identical groups without any balls left over, what is the greatest number of groups Ivan can make

Here we will show you step-by-step with detailed explanation how to calculate 48 divided by 32 using long division.

Before you continue, note that in the problem 48 divided by 32, the numbers are defined as follows:

48 = dividend

32 = divisor

Step 1:

Start by setting it up with the divisor 32 on the left side and the dividend 48 on the right side like this:

 32⟌48  

Step 2:

The divisor (32) goes into the first digit of the dividend (4), 0 time(s). Therefore, put 0 on top:

       0    

 32⟌48  

Step 3:

Multiply the divisor by the result in the previous step (32 x 0 = 0) and write that answer below the dividend.

       0    

 32⟌48  

       0    

Step 4:

Subtract the result in the previous step from the first digit of the dividend (4 - 0 = 4) and write the answer below.

       0    

 32⟌48  

     -0    

       4    

Step 5:

Move down the 2nd digit of the dividend (8) like this:

       0    

 32⟌48  

     -0    

       48  

Step 6:

The divisor (32) goes into the bottom number (48), 1 time(s). Therefore, put 1 on top:

       01  

 32⟌48  

     -0    

       48  

Step 7:

Multiply the divisor by the result in the previous step (32 x 1 = 32) and write that answer at the bottom:

       01  

 32⟌48  

     -0    

       48  

     32  

Step 8:

Subtract the result in the previous step from the number written above it. (48 - 32 = 16) and write the answer at the bottom.

       01  

 32⟌48  

     -0    

       48  

     -32  

       16  

You are done, because there are no more digits to move down from the dividend.

The answer is the top number and the remainder is the bottom number.

Therefore, the answer to 48 divided by 32 calculated using Long Division is:

1

16 Remainder

answer:   14

step-by-step explanation:          

pu you stank bo u ugly bo lol

answer: i can’t tell you that

step-by-step explanation: