What is the equation of the line that is parallel to the line 2x − y = 3 and passes through the point (2, −1)? A. y = −½ x − 5

B. y = −½ x − 1

C. y = 2x − 5

D. y = 2x − 1

C. y = 2x − 5

Step-by-step explanation:

Given equation of line

2x − y = 3

rewriting the equation in slope intercept form as answer are given slope intercept form

y = 2x - 3

slope intercept form of equation is

y = mx + c

where m is the slope

c is y intercept

thus

slope for y = 2x - 3 when comparing with y = mx + c is 2

now we know slope of two parallel line is same

thus,

the slope of  line that is parallel to the line 2x − y = 3

is 2

Let the equation of required line be y = mx + c

where m = 2

thus

y = 2x + c is the new required equation

it passes through the point (2, −1)

using y = -1 and x = 2 in y = 2x + c

-1 = 2*2 + c

c = -1 - 4

c = -5

thus,

equation of required line is option c

y = 2x - 5 answer

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .