The length of a rectangle is 59 inches greater than twice the width. if the diagonal is 2 inches more than the length, find the dimensions of the rectangle.

D=2+20+2w=22+2w
so the eqations would be l=20+2w and d=22+2w
so when solving for the width, (20+2w)^2+w^2=(22+2w)^2
  your equation would be   :                                         400+80w+4w^2+w^2=484+44w+w^2
the anwer would be 1.9226

                                                   

It is the top one. the answer is -7. that is smallest