In ABC, m∠A is 16 less than m∠B , and m∠C is 32 less than twice the m∠B .
Find m∠A.

`1234567890-=/*-qwertyuiop[]asdfghjkl; '\\zxcvbnm,./+ /

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: