A radiator contains 8 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze? pls help i have an important test

Step-by-step explanation:

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1.6 quarts

Step-by-step explanation:

Given : A radiator contains 8 quarts of fluid, 40% of which is antifreeze.

[40% can be written as 0.40.]

Then, the amount of antifreeze in radiator =                                                                                               (1)

If a radiator contains 8 quarts of fluid with 60% of which is antifreeze.

[60% can be written as 0.60.]

Then, the amount of antifreeze in radiator =                                                                                              (2)

Now subtract (1) from (2) we get,

The amount of fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze :-

Hence, the 1.6 quarts of fluid should be drained  and replaced with pure antifreeze so that the new mixture is 60% antifreeze

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explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!