How can you tell when an equation in one variable has infinitely many solutions or no solution? When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You also will end up with a true statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will also end up with a false statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will end up with a true statement, like 2 = 2 for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You will end up with a false statement, like 0 = 2 for an equation with infinitely many solutions.

How can you tell when an equation in one variable has infinitely many solutions or no solution?

When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You also will end up with a true statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will also end up with a false statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will end up with a true statement, like 2 = 2 for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You will end up with a false statement, like 0 = 2 for an equation with infinitely many solutions.

Step-by-step explanation:

There you go homies

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.