I WILL GIVE BRAINLIEST What is the equation in slope-intercept form of a line that is perpendicular to y=2x+2 and passes through the point (4, 3)?

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y =

x =

y=-1/2x+5

x=-2y+10

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula  

y − y 1 = m ( x − x1 ) to find the line perpendicular to  y = 2 x+ 2.

To solve for x you -5 from both sides to get y-5=-1/2x then multiply both sides by -2 to get -2y+10=x which is the same as x=-2+10

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