Find three nonzero vectors a, b, and c such that a × b = a × c != 0 but b != c.

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  a = {1, 2, 3}, b = (2, 4, 7}, c = (-3/14, -3/7, 5/14}

Step-by-step explanation:

For the above vectors, ...

  a × b = a × c = (2, -1, 0)

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Here, c is found to be a scaled version of (a×(a×b)).

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.

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