Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10

Step-by-step explanation:

Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

y = 3/2x + 5

since both lines are parallel they must have the same gradient which is 3/2

y = 3/2x + c

All you have to do now is to replace x and y with (2, -5) to find c

x = 2

y = -5

-5 = 3/2 × 2 + c

-5 = 3 + c

c = -5-3

c = -8