What is the length of TH, when T (6, 9) and H (-4, -1)?

d = 10 sqrt(2)

Step-by-step explanation:

The distance formula is

d = sqrt( (y2-y1) ^2 + ( x2-x1)^2)

d = sqrt( (-1-9) ^2 + ( -4-6)^2)

d = sqrt( (-10) ^2 + ( -10)^2)

d = sqrt( 100+100)

d = sqrt(200)

d = sqrt( 200*2)

d = sqrt(100) sqrt(2)

d = 10 sqrt(2)

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

hi how are you doing today? if you ever need just tell me

step-by-step explanation: