The following data values represent a sample. What is the variance of the sample? = 7. Use the information in the table to help you.
Х
75 11
1
11
(x; - 7)2 0 4 16 36 16
A. 18
B. 4.2
C. 14.4
D. 3.8

step-by-step explanation:

step-by-step explanation:

a'(12.5,11.25)

slope=(y1-y2)/(x1-x2)

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

the answer is a and d