a conference hall has 33 rows. the last row contains 80 seats each row has two fewer seats than the row behind it. how many seats are there second to the last row?

there are 84 seats in the  second to the last row

Step-by-step explanation:

Given that

each row has two fewer seats than the row behind it

It means that

if first row has x seats then

no of seat in second row has (x-2) seats.

and similarly

no of seat in third  row =no of seat in second row - 2seats.

no of seat in third  row = (x-2) seat - 2 seats = x - 4 seats

Given that

last row has 80 seats

let the number of seat in first to the last row be x

then number of seat in last row = x-2

we know number of seat in last row = 80

thus

x - 2 = 80

x = 82

Thus,

the number of seat in first to the last row is 82

Similarly let the number of seat in second to the last row be y

then number of seat in first to the  last row = y-2

since number of seat in first to the last row is 82

thus

y-2 = 82

y = 82 + 2 = 84

Thus, there are 84 seats in the  second to the last row.

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step-by-step explanation: