A square with sides of length eight units, sits on a graph with its lower left hand corner at the origin (0,0). This square is translated five units up, and seven units left. What are the coordinates of the upper right hand corner after translation? Explain. PLEASE HELP ME ON THIS QUESTION. I don’t understand. Only answer if you know because you will receive consequences with monitor.

The coordinates of the upper right hand corner after translation is (1, 13)

Step-by-step explanation:

Let us revise the rules of translation

If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y) ⇒ T (x , y) → (x + h , y) If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y) ⇒ T (x , y) → (x - h , y) If the point (x , y) translated vertically up by k units then its image is (x , y + k)→ (x + h , y) ⇒ T (x , y) → (x , y + k) If the point (x , y) translated vertically down by k units then its image is (x , y - k) ⇒ T (x , y) → (x , y - k)

At first let us find the upper right hand corner of the square

∵ Its lower left hand corner at the origin (0,0)

∵ The length of each side of the square is 8 units

→ To find lower right hand corner add 8 to the x-coordinate of the

   lower left hand corner

∴ The lower right hand corner = (0 + 8, 0)

∴ The lower right hand corner = (8, 0)

→ To find upper right hand corner add 8 to the y-coordinate of the

   lower right hand corner

∴ The upper right hand corner = (8, 0 + 8)

∴ The upper right hand corner = (8, 8)

Now Let us find the image of this corner after translation

∵ This square is translated five units up

→ Use the 3rd rule above

∴ Add 5 to the y-coordinate of the point (8, 8)

∴ Its image = (8, 8 + 5)

∴ Its image = (8, 13)

∵ The square is translated seven units left

→ Use the 2nd rule above

∴ Subtract 7 from the x-coordinate of the point (8, 13)

∴ Its image = (8 - 7, 13)

∴ Its image = (1, 13)

The coordinates of the upper right hand corner after translation is (1, 13)

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