HELP ME PLEASE!!
Describe how you can use the factors of a quadratic function to find its zeros.

Factorising the equation into brackets can help you identify where the x-intercepts are (where the function cuts the x-axis)

Step-by-step explanation:

When you factorise the equation it would look something like this:

(x + a)(x + b) = 0

This also means:

x + a = 0        and        x + b = 0

x = -a             and        x = -b

Example:

Find where the function y = 2x² + 8x + 6 cuts the x-axis

Factorise the 2 out (highest common factor)

x² + 4x + 3 = 0

(x + 1)(x + 3) = 0

x = -1 or -3

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

step-by-step explanation:

what was your answer?