Point Q' is the image of (-5,1) under a translation by 6 units to the right and 2 units down

The object coordinate Q is (-11,3 )

Step-by-step explanation:

The translation is given as : ( 6,-2 )

The image coordinates for Q' is ( -5,1 )

So, to get the coordinates of object point Q (x,y), will be;

 Q (x,y)  + ( 6,-2 )---translation ⇒image Q' ( -5,1 )

Thus,

x+6 = -5

x= -5-6= -11

and

y+ -2 = 1

y-2=1

y=1+2 =3

Thus the object point coordinates Q is (-11,3 )

6hryt%4578855

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3