The first side of a triangle is 2 inches shorter than three times the second side. The third side is 1 inch longer than twice the second side. If the perimeter of the triangle is 101 inches, how long is each side? (Answer to get brainliest)

17in, 49in, 35in

Step-by-step explanation:

I did this in my RSM homwork and it is correct.

First, I added the two inches shorter to the 101, then subtracted 1 longer and got 102.

then divide 102 by how many second lengths, 6. so 102 ÷ 6 = 17

17 is the second length.

3x17-2=49 (another length)

2x17+1=35 (last length)

and there is your answer!

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752