In a certain Algebra 2 class of 28 students, 9 of them play basketball and 17 of them play baseball. There are 6 students who play neither sport. What is the probability
that a student chosen randomly from the class plays both basketball and baseball?

Probability of a student playing both basketball and baseball is 4/28 or 14.3%

Step-by-step explanation:

1) Students playing atleast one sport = 28 - 6 = 22

2) N(Basketball ∩ Baseball) = N(Basketball) + N(Baseball) - N (Basketball U Baseball)

N(Basketball ∩ Baseball) = 9 + 17 - 22 = 4

3) Number of students playing both basketball and baseball = 4

Total number of students = 28

Probability of a student playing both basketball and baseball is 4/28

4/28= 0.1428571429 x 100%= 14.3%

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15