Ara is lining the bottom and lateral faces of a drawer with liner paper. The dimensions of the inside of the drawer are 1 yard, 29 inches, and 9 inches. What is the total area in square inches being covered? The total area being covered is square inches.

The total area being covered is 3,528 square inches

Step-by-step explanation:

Mathematically, we can deduce the shape of the drawer using the dimensions.

With the dimensions given, we can infer that the drawer is shaped like a match box which thus is in the shape of a cuboid.

We can then proceed to find the area of the cuboid.

Mathematically, the area of a cuboid can be calculated as;

2(lb + lh + bh)

Kindly note we need to have a uniform unit before we proceed to calculate the area.

Mathematically, 1 yard is 36 inches

So the sides of the drawer measures 36 inches by 29 inches by 9 inches

Thus, the area is thus;

2( 29(9) + 36(29) + 9(36))

= 2(261 + 1044 + 324)

= 2(1629)

So the area of the drawer is 3,528 square inches

homozygous. one is homozygous, while two is heterozygous.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.