Lucia wishes to advertise her business, so she gives packs of 6 red flyers to each restaurant owner and sets of 4 blue flyers to each clothing store owner. At the end of the day, Lucia realizes that she gave out the same number of red and blue flyers. What is the minimum number of flyers of each color? Flyers

12

Step-by-step explanation:

No. of red flyers = 6

No. of blue flyers = 4

We need to find the minimum number of flyers of each color if she gave out the same number of red and blue flyers. For this we must find the LCM of 6 and 4.

Prime factorization of 6 = 2×3

Prime factorization of 4 = 2×2

Lowest common multiple of 6 and 4 = 12

Hence, there are 12 minimum number of flyers of each color

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

step-by-step explanation:

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