Suppose that a box contains 8 cameras and that 4 of them are defective. A sample of 2 cameras is selected at random. Define the random variable X as the number of defective cameras in the sample. Write the binomial probability distribution for X . Round to two decimal places

P(x) = 8Cx * p^x * (1 - p)^(8 - r) ; r = 0, 1, 2

Step-by-step explanation:

Given that:

Total Number of cameras (n) = 8

Defective cameras = 4

X: number of defective cameras

For a binomial distribution :

P(x) = nCx * p^x * (1 - p)^(n - x)

Probability of success (p) on each trial is the same = (total number of samples / number of defective samples) = 8/4 = 0.5

If 2 samples are chosen at random :

Then, the binomial probability distribution will be :

P(x) = 8Cx * p^x * (1 - p)^(8 - r) ; r = 0, 1, 2

72 fudge and 75 toffee

step-by-step explanation:

i hope this : )

nada

step-by-step explanation: