Talia is packing a moving box. She has a square-framed poster with an area of 16 square feet. The cube-shaped box has a volume of 70 cubic feet. Will the poster lie flat in the box? Explain?

We calculate for the dimensions (the length of the sides) of both the poster and the cube. If the length of the side of the poster is shorter compared to that of the box then, the poster will lie flat in the cube. However, if the poster has a length that is longer than that of the cube then, it will not lie flat in the cube.

length of the poster = sqrt (9 ft^2) = 3 ft

length of the cube = cbrt (30 ft^3) = 3.11 ft

Since, the length of the cube is longer compared to the length of the poster then, the poster will lie flat on the cube

show us the graphs dude

step-by-step explanation:

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !