Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (-7,-6); y=-5x+2

The equation in the slope-intercept form is

y = -5x - 41

Step-by-step explanation:

The given equation in the question is;

y = -5x + 2

The equation of a straight line graph can be written in the form;

y = mx + c

where m is the slope and c is the intercept

From here, we can see that the slope m is -5

Since the line is parallel to the new line we are trying to write its equation, it means that they have the same value of intercept.

Hence, the slope of the new line is also -5

Now, we can write the equation of the new line as;

y = -5x + c

we need to get the value of c here however

To get the value of c, we need to input the value of x and y

From the graph, x = -7 and y = -6

Substituting these values, we have;

-6 = -5(-7) + c

-6 = 35 + c

c = -6 -35

c = -41

So the equation of the new line will be;

y = -5x - 41